Abstract:
Summary. An arithmetical solution is obtained for the viscous creeping flow past a circular cylinder on the bottom of a channel roughly two diameters deep. The top of the channel is assumed to be in uniform motion so a shear layer exists in the undisturbed channel. The drag of the cylinder is found to be equivalent to 29 times the floor drag on an area equal to the projected area of the cylinder. The resultant vertical force on the cylinder is zero.
